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eunjucha
Posts: 1
Registered: ‎11-21-2011

Thermal Load

518 Views, 1 Replies
11-21-2011 05:51 PM

Hi,

 

I would like to know the formula of thermal load for steel you have on load definition based on BS5950 and BS8110.

i try to put the temperature difference of dT 10C in TZ direction and run annalysis.

i expect the emperature induced loads accounted for 10% to 20% of the total axial load though, it does account less than 1 to 2 % of the total axial load in the results.

 

i have the formula of it , Pt, which is following

Pt = 1.2xk x A x E x (12x10-6) x TD

1.2 = load factor

k = Thermal expansion factor = 0.8

A = Gross area of section of steel

E =Modulus of Elasticity of steel =  205 kN/mm2

TD = temp difference (C)

 

please help me up to solve that problem.

 

thanks and regards,

EunJu

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Artur.Kosakowski
Posts: 4,544
Registered: ‎12-17-2010

Re: Thermal Load

11-21-2011 11:48 PM in reply to: eunjucha

You should define TX instead. TZ (or TY) being the difference of temperature between top and bottom (left and right) fibers cause bending rather than tension/compression. See http://docs.autodesk.com/RSA/2012/ENU/filesROBOT/GUID-E4AB6038-D264-45C9-80F9-B06BC687794-448.htm

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski
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