Hi All,
I did some tests to using offset in order to simulate actual conditions in which two different beams frame into a node. The slab supported by the principal beams is simulated as an orthotropic flexible on the xy plane diaphragm as shown in picture.
The offset influence on the structure behavior is not clear. I don’t understand.
If you consider the beam 33 and the column 14 and try to test the equilibrium of the moments for the node 23 in YZ plane you will find the following values (beam 33 and column 14 have the same Y local axis direction):
Beam 33 My =26.55
Colum 14 My = -67.03
Beam 34 Mx = -0.52
Beam 40 Mx = 0.52
The equilibrium of moment = -67.03 +26.55+0.52+0.52 = not equal to 0
In the same situation if you don’t apply the offsets the situation changes.
Beam 33 My =47.95
Colum 14 My = -50.04
Beam 34 Mx = -1.04
Beam 40 Mx = 1.04
The equilibrium of moment = -50.04 +47.95+1.04+1.04 = near to 0
how can I check the accuracy of results ?
Any suggestion ?
Solved! Go to Solution.
Solved by Pawel.Pulak. Go to Solution.
Hi Gabriele,
if you have defined the offset in local Z for beam 33 you should consider additionally the moment resulting from FX*offset for this bar.
Moreover some component to moment equilibrium can be given by the plate (its magnitude depends on orthotropic plate properties you defined).
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Hi Pawel,
I understand the Fx contribute to the equilibrium of the node. But what about the torsion moment of the two beams framing into the node (in normal situation o when they have an offset along z axis) ?. Moreover how I can understand the contribution of the ortotropic panels if I don't have any result for that element ?.
As you understand the problem is to explain to someone that in my structure the beam and the column framing in the same node have a different value of the moment.
Do you have some technical description of the procedure used by Robot ?
Thanks
Hi Gabriele,
If beams 34 and 40 have also non-zero offset in local Z you should consider in equilibrium of node 23 not only torsion moments MX from them but also moments resulting from horizontal shear: FY*offset
As concerns participation of the panel in the transfer of moment you can display maps of moments - but it will not give you precisely the participation of slab in node 23. This participation can be obtained as non-zero value when considering all bars adjoining in specific node. If panel would be deleted then equilibrium considering all bars adjoining in specific node should give precise zero.
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Best regards,