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Little Trick : Linear partial load on bars

9 REPLIES 9
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Message 1 of 10
t.sautierr
1103 Views, 9 Replies

Little Trick : Linear partial load on bars

Typically for partitions above beams but not on the whole lengh.

 

Avoid to specify the coordinates on the lenght or to split the bars.

 

 

But needs a cladding, however useful in my opinion.

 

See Ya

9 REPLIES 9
Message 2 of 10
Rafal.Gaweda
in reply to: t.sautierr

No idea what you mean.


Rafal Gaweda
Message 3 of 10
t.sautierr
in reply to: Rafal.Gaweda

example : 

when you have to apply a linear load on bar at 1 meter from support and 1.40m before the end of the bar, it is not easy to define this -> you have to know the lengh, define the load etc .... or to divide the bar into 3 parts and apply a uniform load to it.

 

Instead of doing that you can set 2 points on  the edge of a cladding supported by the bar to define the load as you want, I find this way much easier.

 

That's all 🙂

 

Message 4 of 10
Rafal.Gaweda
in reply to: t.sautierr

Strange = interesting idea but it works
I would personally try to avoid claddings in such situation but...


Rafal Gaweda
Message 5 of 10
t.sautierr
in reply to: Rafal.Gaweda

How do you personnaly do define this kind of loads ?

The tool to define loads on part of a bar is the trapezoidal load, it requires to know the value of the position, doesn't work only with 2 points or am I missing something?

 

One precision : I am used to import the .dxf from the architect in order to see where are the partition and then the loads, maybe that's why I find this a good solution

Message 6 of 10
Rafal.Gaweda
in reply to: t.sautierr

 

How do you personnaly do define this kind of loads ?

The tool to define loads on part of a bar is the trapezoidal load, it requires to know the value of the position,

 

THis way, without generating additional nodes or spliting bars

 

doesn't work only with 2 points or am I missing something?

 

???????????????

 

trap.jpg

 



Rafal Gaweda
Message 7 of 10
t.sautierr
in reply to: Rafal.Gaweda

🙂

 

That's exactly what I want to avoid because I don't to measure each X1 and X2 ... that's why I put nodes

Message 8 of 10
Rafal.Gaweda
in reply to: t.sautierr

As I told you - your choice, your trick 🙂


Rafal Gaweda
Message 9 of 10
t.sautierr
in reply to: Rafal.Gaweda

Oki doki 😉
Message 10 of 10
t.sautierr
in reply to: Rafal.Gaweda

But actually could it be possible to add a the definition x3 :

 

Uasually I know that the load is at xm from the support so to avoid an operation which be repeated a lot of time, would it be possible to have x3 = L - x2 ?

 

Maybe I am the only one to find the current definition not so easy to use ... 🙂

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