Hi,
I'm writng this post because i'm not understanding if i'm facing some Robot issue or not.
Please see this file http://we.tl/YMcsIlpYse
and see the only connection defined on steel connections module. This connection is defined with M20 anchor, look at "Shear of an achor bolt" results, now change M20 to M16 and see the difference:
USING M20: MRk,s =0,20[kN*m]
USING M16: MRk,s =0,00[kN*m]
If i understood CEB design guide correctly they should exist a proportion: (16^3)/(20^3) = 0,51, shouldn't?
In this particulary case i'm getting a connection really far that i was expecting and i'm trying to achieve why.
Thanks in advance.
Solved! Go to Solution.
Solved by Artur.Kosakowski. Go to Solution.
The very small value (in your case the one calculated for M16) is assumed when Ftmax > FtRds2
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This value is not displayed in the note (hand calcs).
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Sorry Artur, i'm not understanding your calculation. Shouldn't be:
Ftmax = (M/arm+N) / (number of bolts) ?
In quick calculation i get almost 50% of the 95kN you got (case 17).
The maximal force in the anchor is calulated as:
Ftmaxyz = Ftmaxy + Ftmaxz +(-) Ftmaxn (+ for compression, - for tension)
Where
Ftmaxy = FT,Rd,y * fabs(Mj,Ed,y)/Mj,Rd,y/nv – force in extreme bolt from Mj,Ed,y
Ftmaxz = FT,Rd,z * fabs(Mj,Ed,z)/Mj,Rd,z/nh – force in extreme bolt from Mj,Ed,z
Ftmaxn = Nj,Ed/n
Nj,Ed, Mj,Ed,y, Mj,Ed,z – internal forces
Mj,Rd,y – Connection resistance for bending My - f(My,N)
Mj,Rd,z – Connection resistance for bending Mz - f(Mz,N)
nh – Number of bolt columns
nv – Number of bolt rows
n – Number of oll bolts
FT,Rd,y - Resistance of a column base in the tension zone
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