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Base Plate Connection - SHEAR OF AN ANCHOR BOLT

5 REPLIES 5
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Message 1 of 6
RRufino
1305 Views, 5 Replies

Base Plate Connection - SHEAR OF AN ANCHOR BOLT

Hi,

 

I'm writng this post because i'm not understanding if i'm facing some Robot issue or not.

 

Please see this file http://we.tl/YMcsIlpYse

 

and see the only connection defined on steel connections module. This connection is defined with M20 anchor, look at "Shear of an achor bolt" results, now change M20 to M16 and see the difference:

 

USING M20: MRk,s =0,20[kN*m]

USING M16: MRk,s =0,00[kN*m]

 

If i understood CEB design guide correctly they should exist a proportion: (16^3)/(20^3) = 0,51, shouldn't?

 

In this particulary case i'm getting a connection really far that i was expecting and i'm trying to achieve why.

 

Thanks in advance.

5 REPLIES 5
Message 2 of 6
Artur.Kosakowski
in reply to: RRufino

The very small value (in your case the one calculated for M16) is assumed when Ftmax > FtRds2

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.

 

 



Artur Kosakowski
Message 3 of 6
RRufino
in reply to: RRufino

Hi Artur,

 

I'm not finding that Ftmax on results tab...can you help me to find it?

Message 4 of 6
Artur.Kosakowski
in reply to: RRufino

This value is not displayed in the note (hand calcs).

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski
Message 5 of 6
RRufino
in reply to: RRufino

Sorry Artur, i'm not understanding your calculation. Shouldn't be:

 

Ftmax = (M/arm+N) / (number of bolts) ?

 

In quick calculation i get almost 50% of the 95kN you got (case 17).

Message 6 of 6
Artur.Kosakowski
in reply to: RRufino

The maximal force in the anchor is calulated as:

 

Ftmaxyz = Ftmaxy + Ftmaxz +(-) Ftmaxn  (+ for compression, - for tension)

 

Where

 

Ftmaxy = FT,Rd,y * fabs(Mj,Ed,y)/Mj,Rd,y/nv – force in extreme bolt from Mj,Ed,y

Ftmaxz = FT,Rd,z * fabs(Mj,Ed,z)/Mj,Rd,z/nh – force in extreme bolt from Mj,Ed,z

Ftmaxn = Nj,Ed/n

 

Nj,Ed, Mj,Ed,y, Mj,Ed,z – internal forces

Mj,Rd,y – Connection resistance for bending My - f(My,N)

Mj,Rd,z – Connection resistance for bending Mz - f(Mz,N)

nh – Number of bolt columns

nv – Number of bolt rows

n – Number of oll bolts

FT,Rd,y - Resistance of a column base in the tension zone

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski

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