.NET

[#1]

Hello,

I use VB.NET design 4 windows for user input in AutoCad, when I hit the next button on the 1st window, then the 2nd window jump out, however, it jumps out behind the Autocad main window. the window 3 and 4 works fine. Is there anyone knows how to fix this little BUG?

Thank you in advanced!

I use VS2010 and AutoCad2011

I use the following to get the 1st window.

<CommandMethod("CoreInput")> _

Public Sub ShowForm()
        Dim ModalForm As Form1 = New Form1()
        Autodesk.AutoCAD.ApplicationServices.Application.ShowModalDialog(ModalForm)
    End Sub

-------------------------------------------------------------

use the following to hide the 1st window and jump out the 2nd window.

Private Sub Button1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Button1.Click
        Dim Form2Open As New Form2
        Form2Open.Show()
        'Form2.Show()
        Me.Hide()
    End Sub

[#2 · Accepted solution]

Why you do not use the Aplication.ShowModalDialog method on your Button_Click event as you did on your Command method?  You are not supposed to call the Form.Show methods directly because it could result in unexpected behavior.

[#3]

It fixed, thanks John!