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Model Making Help

12 REPLIES 12
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Message 1 of 13
ian.j.wilkins
500 Views, 12 Replies

Model Making Help

First, I want the density of this honeycomb structure (File Attached) to be 2%. Unfortunately I have no Idea how to do that. By density I mean how much of the model's bounding box is actually taken up by the model. Does anyone on here have an idea how to make this model the correct density?

 

I have attached the ipt to this post. Feel free to edit and play around with it as much as you want.

 

Second, I want the the dimensions of this honeycomb to be 1000mm long, by 250mm wide, by 40 mm thick.

 

Thid, and finally, I want to add a plate that is 1mm thick on each side of this model. 

 

Any help would be greatly appreciated.

 

 

12 REPLIES 12
Message 2 of 13
Cadmanto
in reply to: ian.j.wilkins

I don't have access at the moment to Inventor, but what material are you looking to make this part out of?

That is where the density comes from.  Have you tried looking up the properties you are looking for on Matweb?

Or are you talking about coring this part out to get to a specific weight?

 

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Message 3 of 13
JDMather
in reply to: Cadmanto

I think the OP is stating that 98% of the volume occupied by the part should be airspace, specifically in the form of hexagonal honycomb.  The remaining solid material (of whatever material).  So unless I am wrong, the question is really about volume, not density.  (although I guess you could look at the total volume occupied in terms of density)


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Message 4 of 13
ian.j.wilkins
in reply to: Cadmanto

This part is essentiall a honeycomb. By density I mean the amount of the bounding box that is actually taken up by the model. As an example, if I were to take a cube that is 1 cubic unit, and than drill a hole through it that removes .5 cubic units of material, the bounding box would be the same, but only 50% of the bounding box is filled by the model. I like to call the amount of the bounding box actually taken up by the model the density. I am sorry if there is another term for this.

 

In the case of my part. I have taken a box and cut out hexagonal prisms. that is how I got the honeycomb shape. However, I would like the percentage of the original box left (the poercentage not removed when a hexagonal prism was cut out) to be 2%. Or in other word the percentage of the bounding box actually taken up by the model to be 2%. 

Message 5 of 13
JDMather
in reply to: ian.j.wilkins

The part you attached was modeled in Pro/E.

 

It might be easier to communicate using native Inventor geometry.


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Message 6 of 13
ian.j.wilkins
in reply to: JDMather

"I think the OP is stating that 98% of the volume occupied by the part should be airspace, specifically in the form of hexagonal honycomb.  The remaining solid material (of whatever material).  So unless I am wrong, the question is really about volume, not density."

 

Yes that is exactly what I am saying JDMather. I am sorry if I am using the wrong term.

Message 7 of 13

That part I attached was actuallty modeled in Rhinocerous 3D, then converted to an STEP, then imported into Inventor. I am not very fluent in inventor, but I am eager to learn.

Message 8 of 13
JDMather
in reply to: ian.j.wilkins


@ian.j.wilkins wrote:

"I think the OP is stating that 98% of the volume occupied by the part should be airspace, specifically in the form of hexagonal honycomb.  The remaining solid material (of whatever material).  So unless I am wrong, the question is really about volume, not density."

 

Yes that is exactly what I am saying JDMather. I am sorry if I am using the wrong term.


I amended my response above.  You question is about overall part density in terms of material/air volume rather than material property density.  In any case, it should be  clear now.


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Message 9 of 13
Cadmanto
in reply to: ian.j.wilkins

Ian,

Unless I am missing something in what you are trying to explain, the density has to do with the molecular makeup of the material.

Meaning the density is the same whether a steel block weighs 5 lbs or 10 lbs.  Density is the same.

It almost sounds like you are actually talking about the mass, not the density.

 

check.PNGIf this solved your issue please mark this posting "Accept as Solution".

Or if you like something that was said and it was helpful, Kudoskudos.PNG are appreciated. Thanks!!!! Smiley Very Happy

 

New EE Logo.PNG

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Best Regards,
Scott McFadden
(Colossians 3:23-25)


Message 10 of 13
Cadmanto
in reply to: JDMather

JD,

Then that being the case, that is exactly what I eluded to in my first posting.  He is wanting to core out the part to get the weight (mass) to a specific amount.  Nothing to do with density.

 

check.PNGIf this solved your issue please mark this posting "Accept as Solution".

Or if you like something that was said and it was helpful, Kudoskudos.PNG are appreciated. Thanks!!!! Smiley Very Happy

 

New EE Logo.PNG

Inventor.PNG     vault.PNG

 

Best Regards,
Scott McFadden
(Colossians 3:23-25)


Message 11 of 13
blair
in reply to: Cadmanto

Looking at your model, do you really need to have it modeled as a honeycomb center with flat solid sheets on each side or would a solid sheet with the appropriate density work. To do any modeling this way would take a lot of work/time when creating assemblies. To create a simple honeycomb door would require the honeycomb core section as one part, then another part for the exterior sheet and another part for the interior sheet (assuming different materials) to create a sub-assembly for the door. Then you would need to add a frame and hinge/latch hardware.

Inventor 2020, In-Cad, Simulation Mechanical

Just insert the picture rather than attaching it as a file
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Message 12 of 13
blair
in reply to: blair

Creating a model like this would slow your system down as Inventor would need to calculate the honeycomb structure for all components even though the structure would not be visible.

Inventor 2020, In-Cad, Simulation Mechanical

Just insert the picture rather than attaching it as a file
Did you find this reply helpful ? If so please use the Accept as Solution or Kudos button below.
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Message 13 of 13
rmerlob
in reply to: ian.j.wilkins

Ok I was bored so I took a crack at this:

 

To make it a bit more manageable I disregarded the broken up hexagons at the edges and just counted the ´´airspace´´ from the complete hexagons, made a spreadsheet to study it and used Excel´s solver to see which value fulfilled the ´´2% density´´.

 

Turns out you need hexagons with a 152 mm width if you want the walls to be 1 mm (based on your model) and achieve 98% ´´emptyness´´. Please note that with my assumption, it doesnt matter how big the model actually is, the only thing that matters is the width-to-wall ratio.

 

plus, if the honeycomb number is reduced then this spreadsheet is less acurate, i.e. the edges start to be more important.

 

RM

 

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