Line on Plane Joint.
Now - try adding a 3D Contact joint between the two parts.
Inventor 2015 locks up on me when I try this.
The CADWhisperer YouTube Channel
Solved! Go to Solution.
Solved by henderh. Go to Solution.
Thanks for reporting this JD, and confirming it rdyson.
I can reproduce it in R2014 and R2015. It's logged and forwarded onto Development as issue 2052.
Best regards,
-Hugh
Hello,
I have the same issue with "not enough memory". Currently I have installed SP1 for Inventor 2015 but the issue still persists. It's very annoying. I can not perform even a simple simulation of an inclined plane with 3D contact.
Best regards,
Martin Madaj
@martin.madaj wrote:
Currently I have installed SP1 for Inventor 2015 ...
I can not perform even a simple simulation of an inclined plane with 3D contact.
Martin Madaj
Where can I download SP1 for Inventor 2015?
Can you attach your assembly here?
The CADWhisperer YouTube Channel
SP1 for Inventor 2015: http://knowledge.autodesk.com/support/inventor-products/downloads/caas/downloads/content/autodesk-in...
Assembly is attached...
Martin
I get the same error when using Spatial and 3D Contact.
I assume you know the alternative methods of Planar or 2D Contact joints.
The CADWhisperer YouTube Channel
Here is an inclined plane with friction problem from my class.
The Dynamic Simulation results match the hand calculations.
Force 2 is just enough force (at specified point and direction) to cause the box to overcome friction and slide up the plane.
Suppress Force to and make Force 1 active.
Force 1 is just enough force to hold the box on the plane.
Students experiment with changing Force 1 or 2 and observing the results.
The CADWhisperer YouTube Channel
Hi there - I am very interested in the inclined plane friction model and would like to better understand your use of the 2D contact joint.
It appears as though you used two vertical surfaces to apply the 2D contact joint, correct ? And if that is the case, than how would friction play into the model as then the normal force needs to act on the bottom surface of the rectangular block as well as the inclined plane top surface. Could you please explain the reasoning ?
Thanks for your help,
Tim
Mechanical Engineer
Tinius Olsen Inc
Horsham Pa
Note that when you are creating the 2D Contact Joint that the selection box asks you to select two Loops.
Selection of the two vertical faces actually is a selection of the edge loop that goes around the faces.
Now imagine that the loops are actually a sketch that you extrude as a surface body mid-plane to infinity.
Go to the Front view of the assembly.
In Dynamic Simulation click and drag the box up and away from the inclined plane.
Now drag it back down and note that when the loops (extruded surfaces to infinity) contact the box stops.
Note also that you can rotate the box and any corner or face on that loop acts as expected in contact.
I think this is only the static friction and forces. If you apply enough force to move the box - I don't think the values are correct.
But you can quickly trial and error hone in on the force that would be just enough to get the box in motion. (or do the hand calcs)
Right click to get to the Properties.
The CADWhisperer YouTube Channel
Thanks very much for the quick reply. Interesting, and that makes sense when you look at some of the tutorials where they sometimes they grab a sketch and sometimes they grab an edge to make the 2D contact. So I guess it doesn't matter which you use since the extruded surface is going to infinity in both directions.
Thanks again !
Tim