Hi, we want to obtain the center of mass of two or more subassemblies within an assembly. Could you please let us know how to do it? The subassemblies may or may not be connected to each other directly. Thanks.
Are you talking about this?
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In Inventor its termed Center of Gravity and it is on the view tab on the visibility section. As long as everything is within one assembly, it will calculate your center of mass. In the drawing you can select the view and choose to show the CoG. Be aware that it shows as a tiny crosshair, so is not easy to see if you don't know where to look from the assembly.
If you are talking about doing a COG between two sub assemblies within in one main assembly it can't do that as far as I know. Unless there is an iLogic rule that would do this.
The COG command I showed you in my first posting only does the overall model.
If you are talking about something different then what I described then please provide more detail.
If this solved your issue please mark this posting "Accept as Solution".
Or if you like something that was said and it was helpful, Kudos are appreciated. Thanks!!!!
Create a new LoD; supress everything else; (save, most likely, because why not?); iProperties:Physical:Update and when it pops up with a warning, select "No" and it will calculate data for the current LoD.
Can't say I specifically remember doing completely disconnected parts or subassemblies, but it has always done the job otherwise, so I would expect proper results.
LoD is Level of Detail. Whenever you suppress a part or assembly in Inventor it creates a LoD view. Suppress all subassemblies but the ones you want and run the CoG (Center of Gravity) from the view tab.
Maybe try the following: In the assembly, right-click on the desired sub-assembly, iproperties->physical. I believe the CoG you see here is related to coordinate system in the assembly.
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