Hi guys, i am new here on the forum, but not new with Inventor. Version i work with is 2011. I want to make Inventor calculate for me the force by which the pendulum acts towards the die ring, which is grounded. In my simulation, i defined material properties of all the parts, gravity, motion around vertical axis is set to constant value. It turns nicely. But, i can not set the die ring to be the position limiting factor to my pendulum and i can not make centrifugal force created by rotation to act on the pendulum. I attach picture of model, which i created to test if this works. Thanks a lot if someone come up with something.
Solved! Go to Solution.
What book are you using to learn Dynamic Simulation?
Can you attach your assembly here?
Hi and thank you for the answer. I do have "Up and Running with Autodesk Inventor Simulation 2011" and "Mastering Autodesk Inventor 2010". I attach the assy here.
I don't think either of those books cover Dynamic Simulation (in any detail), I was thinking more of Wasim Younis book http://www.amazon.com
Yes, but I'm not sure your problem is covered in the book.
I haven't had chance to experiment with your problem.
If you don't have money to purchase the book or if this is your only real need (to solve this particular problem) you might wait a couple of days and see if someone posts a solution (Fridays are usually slow).
It is not a problem to buy some book, if i know there is an sollution in there. I will look if i can find some other book related to this topic. I am still working on that one and won't stop till i get it right. Will use that more than once.Thanks for answer.
There are a couple different ways to go about it. The easiest way is to disable the zero deg/s^2 acceleration imposed motion in Revolution:1. Then you can see the ~63.9 N rolling force between the cylinder and ring.
I also re-constrained the simulation a little bit by removing the zero acceleration imposed motion in Revolution:1, disabled the rolling joint and replaced it with a 2D contact joint between the roller and outer ring. There you can see the contact (action / reaction) force calculated as ~64 Newtons (assembly attached).
Hope this helps! Please let us know if you have any additional questions, comments or suggestions.
Best regards, -Hugh
At first when you mentioned pendulum, and had the zero acceleration imposed motion, I thought you wanted to know the reaction force at the center of rotation due to the centrifugal load of the spinning components. I did a hand calculation and arrived at the same value as DS (158.1 N). You can view the X or Y component of the Revolution :2 joint and see it matches exactly (images attached)
Warm regards, -Hugh
many thanks for your reply. I woul never imagine i could get one like this. Only when i try to open assemblies posted by you, i get Error message saying: "Error in reading RSe stream" so it won't open them. Is there any way to get over this? Another thing, i found out, that you impose motion also on revolution:2 by that little green cross near the joint sign. What motion you impose? Thanks
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