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cam roller constraint....

18 REPLIES 18
Reply
Message 1 of 19
Anonymous
1120 Views, 18 Replies

cam roller constraint....

How would you constrain a cam roller to an inclined plane? There are 3 cam
rollers on 3 inclined planes. The closure the cam rollers are attached to is
on a 1" pitch thread the closure maks a 45 degree turn to open. the cam
rollers follow the inclined plane. I cant constrain it tho, how would you?
See customer files for a screen shot.
18 REPLIES 18
Message 2 of 19
Anonymous
in reply to: Anonymous

Did you try the transitional constraint?

--
Sean Dotson, PE
http://www.sdotson.com
Check the Inventor FAQ for most common questions
www.sdotson.com/faq.html
-----------------------------------------------------------------------
"Mark V" wrote in message
news:F85D9C9A2478C4045D1EE18053B0314E@in.WebX.maYIadrTaRb...
> How would you constrain a cam roller to an inclined plane? There are 3 cam
> rollers on 3 inclined planes. The closure the cam rollers are attached to
is
> on a 1" pitch thread the closure maks a 45 degree turn to open. the cam
> rollers follow the inclined plane. I cant constrain it tho, how would you?
> See customer files for a screen shot.
>
>
Message 3 of 19
Anonymous
in reply to: Anonymous

wow sean was that reply in 30 seconds? i cant pick the 2nd surface in
transition mode

"Sean Dotson" wrote in message
news:41898BC56E3CC90859DC4CB9AED262E6@in.WebX.maYIadrTaRb...
> Did you try the transitional constraint?
>
> --
> Sean Dotson, PE
> http://www.sdotson.com
> Check the Inventor FAQ for most common questions
> www.sdotson.com/faq.html
> -----------------------------------------------------------------------
> "Mark V" wrote in message
> news:F85D9C9A2478C4045D1EE18053B0314E@in.WebX.maYIadrTaRb...
> > How would you constrain a cam roller to an inclined plane? There are 3
cam
> > rollers on 3 inclined planes. The closure the cam rollers are attached
to
> is
> > on a 1" pitch thread the closure maks a 45 degree turn to open. the cam
> > rollers follow the inclined plane. I cant constrain it tho, how would
you?
> > See customer files for a screen shot.
> >
> >
>
>
Message 4 of 19
Anonymous
in reply to: Anonymous

The second surface is the inclined plane? How was it constructed? Try
check the "choose part first" box then click on the part then the surface.

--
Sean Dotson, PE
http://www.sdotson.com
Check the Inventor FAQ for most common questions
www.sdotson.com/faq.html
-----------------------------------------------------------------------
"Mark V" wrote in message
news:E17271AD84A85F6F715824342C21AAB2@in.WebX.maYIadrTaRb...
> wow sean was that reply in 30 seconds? i cant pick the 2nd surface in
> transition mode
>
Message 5 of 19
Anonymous
in reply to: Anonymous

If the inclined plane is straight like a wedge and not circular like a face
of a square thread then the motion will not be linear, i.e. you can not use
an equation to simulate the motion. A face constraint cannot be used. Now if
the roller was barrel shaped that would be different, lovely.

--
Laurence,

Power is nothing without Control
---


"Mark V" wrote in message
news:F85D9C9A2478C4045D1EE18053B0314E@in.WebX.maYIadrTaRb...
> How would you constrain a cam roller to an inclined plane? There are 3 cam
> rollers on 3 inclined planes. The closure the cam rollers are attached to
is
> on a 1" pitch thread the closure maks a 45 degree turn to open. the cam
> rollers follow the inclined plane. I cant constrain it tho, how would you?
> See customer files for a screen shot.
>
>
Message 6 of 19
Anonymous
in reply to: Anonymous

nothing...
the part with the inclined plane is not of a "swept configuration." not like
a helix. its just a rectangular plate with a rise of 0.125" over a run of
11.331". the total width of the plate is something like 13 inches...
"Sean Dotson" wrote in message
news:F2EBA0D0A5DA8F33BF7BD24FF21D25D1@in.WebX.maYIadrTaRb...
> The second surface is the inclined plane? How was it constructed? Try
> check the "choose part first" box then click on the part then the surface.
>
> --
> Sean Dotson, PE
> http://www.sdotson.com
> Check the Inventor FAQ for most common questions
> www.sdotson.com/faq.html
> -----------------------------------------------------------------------
> "Mark V" wrote in message
> news:E17271AD84A85F6F715824342C21AAB2@in.WebX.maYIadrTaRb...
> > wow sean was that reply in 30 seconds? i cant pick the 2nd surface in
> > transition mode
> >
>
>
Message 7 of 19
Anonymous
in reply to: Anonymous

See CF for a very simplified example.

--
Sean Dotson, PE
http://www.sdotson.com
Check the Inventor FAQ for most common questions
www.sdotson.com/faq.html
-----------------------------------------------------------------------
"Mark V" wrote in message
news:365C3FA30699A5E638F56D2AC599D324@in.WebX.maYIadrTaRb...
> nothing...
> the part with the inclined plane is not of a "swept configuration." not
like
> a helix. its just a rectangular plate with a rise of 0.125" over a run of
> 11.331". the total width of the plate is something like 13 inches...
> "Sean Dotson" wrote in message
> news:F2EBA0D0A5DA8F33BF7BD24FF21D25D1@in.WebX.maYIadrTaRb...
> > The second surface is the inclined plane? How was it constructed? Try
> > check the "choose part first" box then click on the part then the
surface.
> >
> > --
> > Sean Dotson, PE
> > http://www.sdotson.com
> > Check the Inventor FAQ for most common questions
> > www.sdotson.com/faq.html
> > -----------------------------------------------------------------------
> > "Mark V" wrote in message
> > news:E17271AD84A85F6F715824342C21AAB2@in.WebX.maYIadrTaRb...
> > > wow sean was that reply in 30 seconds? i cant pick the 2nd surface in
> > > transition mode
> > >
> >
> >
>
>
Message 8 of 19
Anonymous
in reply to: Anonymous

I posted a simplified assembly in cf... the (3) camm rollers ride on the
(3) inclined plane plates. the cam rollers are attached to the disc shaped
plate which would have threads (1" pitch). 1/8 of a turn would fully
disengage the threads.
"Sean Dotson" wrote in message
news:7DDB1AF1DC710656966D40B3F3DE65E8@in.WebX.maYIadrTaRb...
> See CF for a very simplified example.
>
> --
> Sean Dotson, PE
> http://www.sdotson.com
> Check the Inventor FAQ for most common questions
> www.sdotson.com/faq.html
> -----------------------------------------------------------------------
> "Mark V" wrote in message
> news:365C3FA30699A5E638F56D2AC599D324@in.WebX.maYIadrTaRb...
> > nothing...
> > the part with the inclined plane is not of a "swept configuration." not
> like
> > a helix. its just a rectangular plate with a rise of 0.125" over a run
of
> > 11.331". the total width of the plate is something like 13 inches...
> > "Sean Dotson" wrote in message
> > news:F2EBA0D0A5DA8F33BF7BD24FF21D25D1@in.WebX.maYIadrTaRb...
> > > The second surface is the inclined plane? How was it constructed?
Try
> > > check the "choose part first" box then click on the part then the
> surface.
> > >
> > > --
> > > Sean Dotson, PE
> > > http://www.sdotson.com
> > > Check the Inventor FAQ for most common questions
> > > www.sdotson.com/faq.html
> >
> -----------------------------------------------------------------------
> > > "Mark V" wrote in message
> > > news:E17271AD84A85F6F715824342C21AAB2@in.WebX.maYIadrTaRb...
> > > > wow sean was that reply in 30 seconds? i cant pick the 2nd surface
in
> > > > transition mode
> > > >
> > >
> > >
> >
> >
>
>
Message 9 of 19
Anonymous
in reply to: Anonymous

I reposted your files with a new assembly. I didn't nail it down 100% but
if you drag it you can see how it works. A transitional didn't work but a
tangent did.

--
Sean Dotson, PE
http://www.sdotson.com
Check the Inventor FAQ for most common questions
www.sdotson.com/faq.html
-----------------------------------------------------------------------
"Mark V" wrote in message
news:43342C9367E069F3FEC72BD6CE451E86@in.WebX.maYIadrTaRb...
> I posted a simplified assembly in cf... the (3) camm rollers ride on the
> (3) inclined plane plates. the cam rollers are attached to the disc
shaped
> plate which would have threads (1" pitch). 1/8 of a turn would fully
> disengage the threads.
> "Sean Dotson" wrote in message
> news:7DDB1AF1DC710656966D40B3F3DE65E8@in.WebX.maYIadrTaRb...
> > See CF for a very simplified example.
> >
> > --
> > Sean Dotson, PE
> > http://www.sdotson.com
> > Check the Inventor FAQ for most common questions
> > www.sdotson.com/faq.html
> > -----------------------------------------------------------------------
> > "Mark V" wrote in message
> > news:365C3FA30699A5E638F56D2AC599D324@in.WebX.maYIadrTaRb...
> > > nothing...
> > > the part with the inclined plane is not of a "swept configuration."
not
> > like
> > > a helix. its just a rectangular plate with a rise of 0.125" over a
run
> of
> > > 11.331". the total width of the plate is something like 13 inches...
> > > "Sean Dotson" wrote in message
> > > news:F2EBA0D0A5DA8F33BF7BD24FF21D25D1@in.WebX.maYIadrTaRb...
> > > > The second surface is the inclined plane? How was it constructed?
> Try
> > > > check the "choose part first" box then click on the part then the
> > surface.
> > > >
> > > > --
> > > > Sean Dotson, PE
> > > > http://www.sdotson.com
> > > > Check the Inventor FAQ for most common questions
> > > > www.sdotson.com/faq.html
> > >
> > -----------------------------------------------------------------------
> > > > "Mark V" wrote in message
> > > > news:E17271AD84A85F6F715824342C21AAB2@in.WebX.maYIadrTaRb...
> > > > > wow sean was that reply in 30 seconds? i cant pick the 2nd surface
> in
> > > > > transition mode
> > > > >
> > > >
> > > >
> > >
> > >
> >
> >
>
>
Message 10 of 19
Anonymous
in reply to: Anonymous

really? thats interesting..... lemme look

"Sean Dotson" wrote in message
news:856D3C835E3F1A011B1CDF8A4C171A02@in.WebX.maYIadrTaRb...
> I reposted your files with a new assembly. I didn't nail it down 100% but
> if you drag it you can see how it works. A transitional didn't work but a
> tangent did.
>
> --
> Sean Dotson, PE
> http://www.sdotson.com
> Check the Inventor FAQ for most common questions
> www.sdotson.com/faq.html
> -----------------------------------------------------------------------
> "Mark V" wrote in message
> news:43342C9367E069F3FEC72BD6CE451E86@in.WebX.maYIadrTaRb...
> > I posted a simplified assembly in cf... the (3) camm rollers ride on
the
> > (3) inclined plane plates. the cam rollers are attached to the disc
> shaped
> > plate which would have threads (1" pitch). 1/8 of a turn would fully
> > disengage the threads.
> > "Sean Dotson" wrote in message
> > news:7DDB1AF1DC710656966D40B3F3DE65E8@in.WebX.maYIadrTaRb...
> > > See CF for a very simplified example.
> > >
> > > --
> > > Sean Dotson, PE
> > > http://www.sdotson.com
> > > Check the Inventor FAQ for most common questions
> > > www.sdotson.com/faq.html
> >
> -----------------------------------------------------------------------
> > > "Mark V" wrote in message
> > > news:365C3FA30699A5E638F56D2AC599D324@in.WebX.maYIadrTaRb...
> > > > nothing...
> > > > the part with the inclined plane is not of a "swept configuration."
> not
> > > like
> > > > a helix. its just a rectangular plate with a rise of 0.125" over a
> run
> > of
> > > > 11.331". the total width of the plate is something like 13 inches...
> > > > "Sean Dotson" wrote in message
> > > > news:F2EBA0D0A5DA8F33BF7BD24FF21D25D1@in.WebX.maYIadrTaRb...
> > > > > The second surface is the inclined plane? How was it constructed?
> > Try
> > > > > check the "choose part first" box then click on the part then the
> > > surface.
> > > > >
> > > > > --
> > > > > Sean Dotson, PE
> > > > > http://www.sdotson.com
> > > > > Check the Inventor FAQ for most common questions
> > > > > www.sdotson.com/faq.html
> > > >
> >
> -----------------------------------------------------------------------
> > > > > "Mark V" wrote in message
> > > > > news:E17271AD84A85F6F715824342C21AAB2@in.WebX.maYIadrTaRb...
> > > > > > wow sean was that reply in 30 seconds? i cant pick the 2nd
surface
> > in
> > > > > > transition mode
> > > > > >
> > > > >
> > > > >
> > > >
> > > >
> > >
> > >
> >
> >
>
>
Message 11 of 19
Anonymous
in reply to: Anonymous

I see how you did it. But I'm having trouble adapting it to my model.
Specifically, when I "fix the camroller assembly to the plate. Once that
becomes fixed on the axis of rotation the cam no longer climbs.... Thanks
for all the help, I dont want to use all your time!


"Mark V" wrote in message
news:41D12EAFD2E79CD929BFD79BDD66DAED@in.WebX.maYIadrTaRb...
> really? thats interesting..... lemme look
>
> "Sean Dotson" wrote in message
> news:856D3C835E3F1A011B1CDF8A4C171A02@in.WebX.maYIadrTaRb...
> > I reposted your files with a new assembly. I didn't nail it down 100%
but
> > if you drag it you can see how it works. A transitional didn't work but
a
> > tangent did.
> >
> > --
> > Sean Dotson, PE
> > http://www.sdotson.com
> > Check the Inventor FAQ for most common questions
> > www.sdotson.com/faq.html
> > -----------------------------------------------------------------------
> > "Mark V" wrote in message
> > news:43342C9367E069F3FEC72BD6CE451E86@in.WebX.maYIadrTaRb...
> > > I posted a simplified assembly in cf... the (3) camm rollers ride on
> the
> > > (3) inclined plane plates. the cam rollers are attached to the disc
> > shaped
> > > plate which would have threads (1" pitch). 1/8 of a turn would fully
> > > disengage the threads.
> > > "Sean Dotson" wrote in message
> > > news:7DDB1AF1DC710656966D40B3F3DE65E8@in.WebX.maYIadrTaRb...
> > > > See CF for a very simplified example.
> > > >
> > > > --
> > > > Sean Dotson, PE
> > > > http://www.sdotson.com
> > > > Check the Inventor FAQ for most common questions
> > > > www.sdotson.com/faq.html
> > >
> > -----------------------------------------------------------------------
> > > > "Mark V" wrote in message
> > > > news:365C3FA30699A5E638F56D2AC599D324@in.WebX.maYIadrTaRb...
> > > > > nothing...
> > > > > the part with the inclined plane is not of a "swept
configuration."
> > not
> > > > like
> > > > > a helix. its just a rectangular plate with a rise of 0.125" over
a
> > run
> > > of
> > > > > 11.331". the total width of the plate is something like 13
inches...
> > > > > "Sean Dotson" wrote in message
> > > > > news:F2EBA0D0A5DA8F33BF7BD24FF21D25D1@in.WebX.maYIadrTaRb...
> > > > > > The second surface is the inclined plane? How was it
constructed?
> > > Try
> > > > > > check the "choose part first" box then click on the part then
the
> > > > surface.
> > > > > >
> > > > > > --
> > > > > > Sean Dotson, PE
> > > > > > http://www.sdotson.com
> > > > > > Check the Inventor FAQ for most common questions
> > > > > > www.sdotson.com/faq.html
> > > > >
> > >
> > -----------------------------------------------------------------------
> > > > > > "Mark V" wrote in message
> > > > > > news:E17271AD84A85F6F715824342C21AAB2@in.WebX.maYIadrTaRb...
> > > > > > > wow sean was that reply in 30 seconds? i cant pick the 2nd
> surface
> > > in
> > > > > > > transition mode
> > > > > > >
> > > > > >
> > > > > >
> > > > >
> > > > >
> > > >
> > > >
> > >
> > >
> >
> >
>
>
Message 12 of 19
Anonymous
in reply to: Anonymous

See CF for an example "RAMP"

--
Laurence,

Power is nothing without Control
---


"Mark V" wrote in message
news:365C3FA30699A5E638F56D2AC599D324@in.WebX.maYIadrTaRb...
> nothing...
> the part with the inclined plane is not of a "swept configuration." not
like
> a helix. its just a rectangular plate with a rise of 0.125" over a run of
> 11.331". the total width of the plate is something like 13 inches...
> "Sean Dotson" wrote in message
> news:F2EBA0D0A5DA8F33BF7BD24FF21D25D1@in.WebX.maYIadrTaRb...
> > The second surface is the inclined plane? How was it constructed? Try
> > check the "choose part first" box then click on the part then the
surface.
> >
> > --
> > Sean Dotson, PE
> > http://www.sdotson.com
> > Check the Inventor FAQ for most common questions
> > www.sdotson.com/faq.html
> > -----------------------------------------------------------------------
> > "Mark V" wrote in message
> > news:E17271AD84A85F6F715824342C21AAB2@in.WebX.maYIadrTaRb...
> > > wow sean was that reply in 30 seconds? i cant pick the 2nd surface in
> > > transition mode
> > >
> >
> >
>
>
Message 13 of 19
Anonymous
in reply to: Anonymous

It won't! to get this to work then you will have to use a barrel shaped
roller like my example or a single ball bearing in a cup. Like I explained
in my first post. You will also have to give consideration to the way the
carrier is fixed to the mechanism to lift the threaded portion as the non
linear travel of the rollers in Z axis will interfere with the uniform
travel of threaded portion. All that is needed here is some clearance.

--
Laurence,

Power is nothing without Control
---


"Mark V" wrote in message
news:E8DB18D860DA682FC0257925993EE6BD@in.WebX.maYIadrTaRb...
Once that
> becomes fixed on the axis of rotation the cam no longer climbs.... Thanks
> for all the help, I dont want to use all your time!
Message 14 of 19
Anonymous
in reply to: Anonymous

Laurence is right. Since the roller is cylindrical, the "length" of the
face cannot be touching the inclined plane at all points as it rises. I
think you could get by not making it a barrel cam but adding a sketch "ring"
around the cam and using this sketch as your tangent constraint, hence
giving you essentially point contact.

--
Sean Dotson, PE
http://www.sdotson.com
Check the Inventor FAQ for most common questions
www.sdotson.com/faq.html
-----------------------------------------------------------------------
"Laurence Yeandle" wrote in message
news:174FCF79FD97B60568FA930EF1B0CCA1@in.WebX.maYIadrTaRb...
> It won't! to get this to work then you will have to use a barrel shaped
> roller like my example or a single ball bearing in a cup. Like I explained
> in my first post. You will also have to give consideration to the way the
> carrier is fixed to the mechanism to lift the threaded portion as the non
> linear travel of the rollers in Z axis will interfere with the uniform
> travel of threaded portion. All that is needed here is some clearance.
>
> --
> Laurence,
>
> Power is nothing without Control
> ---
>
>
> "Mark V" wrote in message
> news:E8DB18D860DA682FC0257925993EE6BD@in.WebX.maYIadrTaRb...
> Once that
> > becomes fixed on the axis of rotation the cam no longer climbs....
Thanks
> > for all the help, I dont want to use all your time!
>
>
Message 15 of 19
Anonymous
in reply to: Anonymous

Yep.. I agree with the barrel shaped cam. In fact, thats the preffered cam
for this application. I have pointed this out to the engineering group here
a while ago, but there answer has been, well the old design works....
(20+yrs). So... I've put in the barrell cam, and no one is the wiser! i'm
so sneaky... Anyhow, thanks fellas for the assistance!
Message 16 of 19
Anonymous
in reply to: Anonymous

I don't know how heavy duty the application is? If light you could get away
with straight rollers but heavy and the roller corners would score the cam
face though possible with clearance on roller's bearing/ bush will allow
tilting of roller to some degree. A light and small application and you
would never notice. Sean's method for a constraint would be simpler than my
set up , don't see why it would not work.

--
Laurence,

Power is nothing without Control
---


"Mark V" wrote in message
news:95B76559237FE24E229928DD2853934B@in.WebX.maYIadrTaRb...
> Yep.. I agree with the barrel shaped cam. In fact, thats the preffered
cam
> for this application. I have pointed this out to the engineering group
here
> a while ago, but there answer has been, well the old design works....
> (20+yrs). So... I've put in the barrell cam, and no one is the wiser! i'm
> so sneaky... Anyhow, thanks fellas for the assistance!
>
>
Message 17 of 19
Anonymous
in reply to: Anonymous

Basically Laurence, the cam rollers (3) hold the weight of a threaded
closure 2181lbs, and a seal plate 808lbs, plus a tooling basket with parts
that may be 800lbs... the threads on the closure are 27" -1 modified
butress thread. the threads never come into contact with each other, the cam
rollers assure this. the pitch of the cam riser plate is machined to match
the threads of the closure.
The above assembly lowers into a pressure vessel threads on the closure
threading into the vessel as detailed above, then presure is introduced into
the vessel, 5000psi (tinkertoy stuff for us).
cool huh.. 🙂


"Laurence Yeandle" wrote in message
news:FF8C03D3B30F98126D54226418968E1A@in.WebX.maYIadrTaRb...
> I don't know how heavy duty the application is? If light you could get
away
> with straight rollers but heavy and the roller corners would score the cam
> face though possible with clearance on roller's bearing/ bush will allow
> tilting of roller to some degree. A light and small application and you
> would never notice. Sean's method for a constraint would be simpler than
my
> set up , don't see why it would not work.
>
> --
> Laurence,
>
> Power is nothing without Control
> ---
>
>
> "Mark V" wrote in message
> news:95B76559237FE24E229928DD2853934B@in.WebX.maYIadrTaRb...
> > Yep.. I agree with the barrel shaped cam. In fact, thats the preffered
> cam
> > for this application. I have pointed this out to the engineering group
> here
> > a while ago, but there answer has been, well the old design works....
> > (20+yrs). So... I've put in the barrell cam, and no one is the wiser!
i'm
> > so sneaky... Anyhow, thanks fellas for the assistance!
> >
> >
>
>
Message 18 of 19
Anonymous
in reply to: Anonymous

I posted another file which is more accurate and simpler than the first
(under your original in CF) RAMP B, It uses a tangent constraint my first
file used a point contact which was fixed on the roller which is incorrect
but served its purpose. In the new file you will see two angles one is the
riser plate 8.53 and if you drive the arm to 180 degrees and apply you will
see the angles match. The angle shown on the roller is the angle the arm
makes with the riser plate. Drive the arm to start 90 degrees and apply, the
angle is zero or in this case shows 180 same thing. In an ideal situation
the angle the arm makes with the riser plate should remain constant and in
the case of a helical riser plate cut like a thread it would. The new model
uses a tangent constraint and the roller is kept in correct position on the
riser plate. I am assuming cause the constraint tries to maintain its
optimum position which just happens to be perpendicular (which is made
perpendicular to the sketch partE and its path it makes with the riser plate
face at that point)

The riser plate will not match the natural path of the threaded portion but
I assume that the riser plate is set at helix angle of thread, this will be
an average at least. If you look closely at the contact of partE with the
riser plate and in different positions of the arm it can be seen that the
contact on the roller moves around, this is what you would expect with the
varying angles.

--
Laurence,

Power is nothing without Control
---


"Mark V" wrote in message
news:B321B76BC27E7521DD3EB822330ECDEE@in.WebX.maYIadrTaRb...
> Basically Laurence, the cam rollers (3) hold the weight of a threaded
> closure 2181lbs, and a seal plate 808lbs, plus a tooling basket with parts
> that may be 800lbs... the threads on the closure are 27" -1 modified
> butress thread. the threads never come into contact with each other, the
cam
> rollers assure this. the pitch of the cam riser plate is machined to match
> the threads of the closure.
> The above assembly lowers into a pressure vessel threads on the closure
> threading into the vessel as detailed above, then presure is introduced
into
> the vessel, 5000psi (tinkertoy stuff for us).
> cool huh.. 🙂
Message 19 of 19
Anonymous
in reply to: Anonymous

excellent! thanks Lawrence!
"Laurence Yeandle" wrote in message
news:39DC7004BD51754426F0CF3E431B38FD@in.WebX.maYIadrTaRb...
> I posted another file which is more accurate and simpler than the first
> (under your original in CF) RAMP B, It uses a tangent constraint my first
> file used a point contact which was fixed on the roller which is incorrect
> but served its purpose. In the new file you will see two angles one is the
> riser plate 8.53 and if you drive the arm to 180 degrees and apply you
will
> see the angles match. The angle shown on the roller is the angle the arm
> makes with the riser plate. Drive the arm to start 90 degrees and apply,
the
> angle is zero or in this case shows 180 same thing. In an ideal situation
> the angle the arm makes with the riser plate should remain constant and in
> the case of a helical riser plate cut like a thread it would. The new
model
> uses a tangent constraint and the roller is kept in correct position on
the
> riser plate. I am assuming cause the constraint tries to maintain its
> optimum position which just happens to be perpendicular (which is made
> perpendicular to the sketch partE and its path it makes with the riser
plate
> face at that point)
>
> The riser plate will not match the natural path of the threaded portion
but
> I assume that the riser plate is set at helix angle of thread, this will
be
> an average at least. If you look closely at the contact of partE with the
> riser plate and in different positions of the arm it can be seen that the
> contact on the roller moves around, this is what you would expect with the
> varying angles.
>
> --
> Laurence,
>
> Power is nothing without Control
> ---
>
>
> "Mark V" wrote in message
> news:B321B76BC27E7521DD3EB822330ECDEE@in.WebX.maYIadrTaRb...
> > Basically Laurence, the cam rollers (3) hold the weight of a threaded
> > closure 2181lbs, and a seal plate 808lbs, plus a tooling basket with
parts
> > that may be 800lbs... the threads on the closure are 27" -1 modified
> > butress thread. the threads never come into contact with each other, the
> cam
> > rollers assure this. the pitch of the cam riser plate is machined to
match
> > the threads of the closure.
> > The above assembly lowers into a pressure vessel threads on the closure
> > threading into the vessel as detailed above, then presure is introduced
> into
> > the vessel, 5000psi (tinkertoy stuff for us).
> > cool huh.. 🙂
>
>

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