Help a poor programmer again!
What is the best way to create a workplane at a given angle on the surface of the tube. Imagine the workplane long and thin running along the surface of the tube. The angle will be a parameter (from a sketch or user).
I'd like the workplane to always be on the surface of the tube, even when the diameter of the tube (from a dimension in a sketch) changes.
I'm thinking that a (angled) line in the same sketch as the two circles (which define the tube diameter and thickness) would be a good starting point, but I'm open to better suggestions from more experienced Inventor users...
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Attach example file here.
A sketch line sounds like the solution.
Make the diameter of the tube a parameter also and use that for the offset of the plane.
I would use the sketch method aswell, drawings a construction line from he centre of the circle to the circumference of the circle. Then create a plane that is perpenicular to the construction line (select line) and placed at the end of the line (select end of line).
Yes, I've done something similar. I made a sketchpoint be an intersection between the line and the circle, then used workplane tangent to surface through point.
I'm slowly learning...
"Make the diameter of the tube a parameter also and use that for the offset of the plane."
Is this more or less preferable to having a point at the intersection of a the line and circle? That way the point position is driven by the two entities directly (circle diameter and line angle) rather than an offset.
I'm a beginner, so all opinions welcome!
@oransen wrote:JDMather, thanks for the reply.I can't see an attachment though...
My request was for YOU to attach a file here that exhibits the issue you want to solve.
When you respond (on web) you should see Attachments link below the text box.