Autodesk Survey Products

[#1]

Has anyone come across or have a solution for labeling lines with SURVEYOR’S UNITS on. If you select SURVEYOR’S UNITS under FORMAT UNITS, this will show an angle in bearing format under properties for a selected object. But, if you label a line with SURVEYOR’S UNITS on, you get miscellaneous characters for a bearing. Only DISTANCE will show properly.

I am running LD 2004 with the Service Pack 2 and the problem still has not been fixed. I have also tried this on multiple desktops and get the same result.

Does anyone else have this problem?

[#2]

I can duplicate this behavior, but I wouldn't be waiting on
a fix since LDD is designed to operate with the system
variable AUNITS set to 1 (Deg\Min\Sec), so when you switch
to Surveyors Units, you're on your own.

What have our own routine for listing angles that reports
surveyor units without having to change the AUNITS setting.

FYI: this NG is primarily for Autodesk's standalone survey
product (Field Survey), future questions will get more
attention in this group:
news://discussion.autodesk.com/autodesk.land-desktop/


"wsi" wrote in message
news:f1a47b5.-1@WebX.maYIadrTaRb...
> Has anyone come across or have a solution for labeling
lines with SURVEYOR'S UNITS on. If you select SURVEYOR'S
UNITS under FORMAT UNITS, this will show an angle in bearing
format under properties for a selected object. But, if you
label a line with SURVEYOR'S UNITS on, you get miscellaneous
characters for a bearing. Only DISTANCE will show properly.
> I am running LD 2004 with the Service Pack 2 and the
problem still has not been fixed. I have also tried this on
multiple desktops and get the same result.
>
> Does anyone else have this problem?
>
>

[#3]

Correction:
> news://discussion.autodesk.com/autodesk.land-desktop

[#4]

i have had this problem as well...usually everything works fine and the labels get changed to gibberish by some trigger....rotation of lines, creation of new viewports, ect.

[#5]

I have a parcel I am drawing out and have run into the situation where I am unable to continue because lack of understand exactly how to accomplish this task... so if anyone could help, please.
I get to this point and this is where it losses me: A northerly non-tangent curve having a radius of 637.5 feet, concave westerly, whose radius bears N. 83 degrees 52' 46" W., through an angle of 5 degrees 54'38" an arc length of 65.76 feet.
If anyone can follow that and can turn it into ACAD command line directions, I would be MOST appreciative!

[#6]

acadartist said the following On 12/6/2006 12:27 PM:
> I have a parcel I am drawing out and have run into the situation where I am unable to continue because lack of understand exactly how to accomplish this task... so if anyone could help, please.
> I get to this point and this is where it losses me: A northerly non-tangent curve having a radius of 637.5 feet, concave westerly, whose radius bears N. 83 degrees 52' 46" W., through an angle of 5 degrees 54'38" an arc length of 65.76 feet.
> If anyone can follow that and can turn it into ACAD command line directions, I would be MOST appreciative!

I'm not sure what software you have, but you can do the following with
nothing more than vanilla AutoCAD.

Create a line from the end of the previous segment 637.5' long at a
bearing of N83d52'46"W.
This will locate the center point.
Then copy this line in place (on top of itself).
Rotate one of these lines the delta angle (5d54'38")
Now you have both endpoints, and the center point.
Use the regular ._ARC command to draw the arc.

For more info, see:
http://www.cadtutor.net/tutorials/autocad/survey_data.php


--
R.K. McSwain
http://rkmcswain.blogspot.com

[#7]

Thank you, that was very helpful... this was my first attempt ever at surveyor's units and this situation was beyond me but you made it clearer.