Autodesk Robot Structural Analysis

[#1]

Hello,

what I'd like to know is:

does "Released direction" mean that there is no restraint in that direction?

For example, does released direction Ux+ mean "no restraint in Ux+"?

In the attached sketch you can see my doubt.

Thank you.

[#2]

Take a look at this help topic:

http://docs.autodesk.com/RSA/2012/ENU/filesROBOT/GUID-A65C66FB-20DA-4B7C-BFE2-3A7B0CF54F7-249.htm

UX+\- shows different direction depending on bar start \ end

[#3]

Oh, yes! ... But I think that it is exactly the opposite!

[#4]

Take a look below, no compression (yellow diagram , Fx force) on right hand side beam due to release Ux+ defined at the beginning of this bar, tension in left bar

[#5]

I think the problem is solved:
let's take a look to the central node; the situation should be



this means that the 1st node of the 2nd bar is free in Ux+, while the whole bar is free in Ux-.
Due to the fact that there is a DSC element (is it correct?), the node and the bar move in opposite directions.
So the "beginning node of the bar element" (User's guide) is the node 1 of my sketch, while I intended that it was the "new node" of my sketch (they can move in opposite directions).

Giorgio

[#6 · Accepted solution]

DSC algorithm creates connections between phisical node (on your screen capture node 1, on mine (below) node 2) and calculation node (on your screen capture "new node", on mine  - node 10).

In our situation (unidirectional realease UX+) such link does not exist between these two nodes only in UX+ direction so node 1 (or 2 on my example) can be displaced but your "new node" (mine node 10) remains in the same position.

In case of opposite direction force these nodes will act toghether: