Autodesk Inventor

[#1]

Trying to do something as simple as y=x^3 (Explicit Mode). Set xmin = 10, xmax = 20 then tried y(x) = :

1in *(x^3) -- no good

(x^3)/1 in -- no good

(x/1 in)^3 -- no good

Error is that "Equation y(x) contains errors. Expected units are length".

The point here is: Why should tpying in such a simple equation as y=x^3 be so difficult??? Can't even do (x*x*x)/1 in & make it work.

It's really great that the example shows an airfoil equation, but how about starting with the simple stuff & getting it to work right first???

[#2]

Try something like this

oops, but inches (in) as your units and of course the 25 was just a test number.

[#3]

marshallw,

When creating explicit equations, the units for xmin and xmax are length. So your equation is (x^3) / (1 in * 1 in) so you end up with in for the end units. 

The Tutorial for equation curves uses simpler equations that what are shown in the airfoil video. 

[#4]

Thank you Patrick & JD. I noticed that both you solutions involved dividing x^3 by 1{measurement unit}^2. I would have never thought of dividing x^3 by something squared to get the answer, which was exactly my point to Autodesk on the original post -- whay so dang complex?

Are you folks saying that I have to take into accound the units for both xmin & xmax in the equation? Is that the reason for dividing by 1{unit}^2/

Marshall

[#5]

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marshallw wrote:

 I would have never thought of dividing x^3 by something squared to get the answer, which was exactly my point to Autodesk on the original post -- whay so dang complex?

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Seems pretty logical to me - I recall learning how to handle units in HS math.