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Question about Trig functions in Paremeters
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146 Views, 1 Replies
11-28-2011 08:03 PM
Hello All
Lately it seems the only questions I have to ask is to do Parametric Trig equations.
So here we go again.
I am creating an equation driven part with a few Trig eqautions. (Not that difficult until now)
One equation I need to input requires the Trig function Cotangent (cot).
eg. cot (x deg / n ul) with the unit type set at (ul)
This syntax does not work.
But when I rewrite the equation as 1 ul / tan (x deg / n ul) or tan (x deg / n ul)^-1 ul I get the result that cot should give me.
Does Inventor not support the Cotangent, Secant or Cosecant functions?
Or am I just misrepresenting the syntax description?
Thanks Clint
Inventor 2012 Professional
Inventor 2012 Professional
Re: Question about Trig functions in Paremeters
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11-29-2011 01:02 AM in reply to:
cwilko
list of valid functions (in "References" -> "Use formulas and equations" -> "Functions")
no cot, so guess you're stuck with 1/tan
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Please mark this response as "Accept as Solution" if it answers your question - but note that the solution may not be the answer you're wanting to hear...
Lithium - helping nntp users with mania, depression and headaches

