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PRESSURE LOADS IN AUTOCAD INVENTOR
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When adding pressure loads to a perpindicular face inventor states that the pressure is applied uniformly to the selected face.
As an example a disc of 300 mm dia(area= 70685 sq mm) with a uniform pressure load of 10MPa.
The Question is this !
Is the 10MPa load input construed by inventor as 10MPa per square mm or 10MPa over the entire disc area.
which is the correct interpretation?
Solved! Go to Solution.
Re: PRESSURE LOADS IN AUTOCAD INVENTOR
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10MPa total over the area.
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Re: PRESSURE LOADS IN AUTOCAD INVENTOR
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Thanks for the reply,if that is the case then i will have to rethink the plate thickness,the deflection seems awfully
high.
just for the record the input is as follows.
Plate dia = 488mm
thickness say 12 mm
pressure on plate area 29 psi(0.199 Mpa)
plate constraint on perimeter.
material .mild steel
analysis shows max displacement =0.48
If you wish have a look.
Regards
methoni
Re: PRESSURE LOADS IN AUTOCAD INVENTOR
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oops, let me wake up a bit and look at this again.
...back in a while.
In any case - it should be really easy to do a couple of virtual experiments to verify.
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Re: PRESSURE LOADS IN AUTOCAD INVENTOR
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The answer is in your question. What's a MPa?
A MPa is 1,000,000 N/m² or 1 N/mm²
which is an expression of pressure.
Win 7 64 bit
Re: PRESSURE LOADS IN AUTOCAD INVENTOR
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Thanks for your input.
What started out as a simple problem now seems to be confusing.
So are you saying that if you enter a figure in inventor of say 10MPa,inventor knowing the surface area of plate(from original sketch input calculates the total load over the plate area.
The deflection/stress is then derived from this extrapolation.
Does this make sense ?
Re: PRESSURE LOADS IN AUTOCAD INVENTOR
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That makes sense.
As JD suggested, experiment. Try some simple exercises for which you can determine the results using classical methods until you're comfortable with the FEA interface.
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Re: PRESSURE LOADS IN AUTOCAD INVENTOR
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There is a difference between "Pressure" and a "Force" load in Inventor. A pressure load of 10 psi on a 12" x 12" plate will produce a total "load" of 1440 lb. A "Force" load of 10 lb on a 12" x 12" plate will produce a total "load" of 10 lb.
The pressure load will always be acting perpendicular to the surface whereas a force load can be in any direction (vector) to the surface.
The area that Inventor will use is dependent of the units used. If you are using Imperial and apply a 10psi, then the load force will be the 10 lb on every square inch.
So a Pa is force of one Newton per square Meter and a MPa is 1,000,000 Pa
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