if i already have the variables for an alignment that has spirals in it and have the northing easting and stations of all the data
for example see below.....how could i input all this into the alignment by layout command? or what would be the best way to draw this known data in Civil 3D?
SP13015 N 7465677.983 E 2645471.601 Z -99999.990 STA 1+000.000
Distance 31.322 m Azimuth 37°56'18.9"
SP13016 N 7465702.686 E 2645490.858 Z -99999.990 STA 1+031.322
Distance 0.000 m Azimuth 37°57'54.1"
SPIRAL SPR1029
TS N 7465702.686 E 2645490.858 STA 1+031.322
SI N 7465715.832 E 2645501.107
SC N 7465722.653 E 2645505.896 STA 1+056.322
Long Tangent 16.669 m
Short Tangent 8.335 m
Long Chord 24.997 m
Direction Back 37°56'18.9"
Direction Ahead 35°04'25.6"
Spiral Length 25.000 m
Spiral Angle 2°51'53.2"
Offset 0.000 m
Degree at Start 0°00'00.0"
Degree at End 6°59'07.8" R2 250.000 m
Xs 24.994
Ys -0.417
p 0.104
k 12.499
k' 0.104
Distance 0.000 m Azimuth 218°05'58.8"
CURVE CUR1021
PC N 7465722.653 E 2645505.896 STA 1+056.322
CC N 7465866.311 E 2645301.293
PI N 7465749.087 E 2645524.456 STA 1+088.621
TAN 32.299 m
DB 35°04'25.6"
DA 20°21'01.8"
LChord Distance 64.066 m Azimuth 27°42'43.7"
External Distance 2.078 m
Middle Ordinate 2.061 m
Radius 250.000 m
DEG 6°59'07.8"
DELTA -14°43'23.8"
LENGTH 64.242 m
PT N 7465779.371 E 2645535.689 STA 1+120.564
CURVE CUR1021
Distance 0.000 m Azimuth 200°20'38.8"
SPIRAL SPR1030
CS N 7465779.371 E 2645535.689 STA 1+120.564
SI N 7465798.933 E 2645542.945
ST N 7465839.534 E 2645552.459 STA 1+183.064
Long Tangent 20.864 m
Short Tangent 41.701 m
Long Chord 62.457 m
Direction Back 20°21'01.8"
Direction Ahead 13°11'18.7"
Spiral Length 62.500 m
Spiral Angle 7°09'43.1"
Offset 0.000 m
Degree at Start 6°59'07.8" R1 250.000 m
Degree at End 0°00'00.0"
Xs 62.402
Ys -2.601
p 0.651
k 31.234
k' 0.651
Distance 0.000 m Azimuth 359°11'49.0"
