Member
Posts: 3
Registered: ‎12-06-2013
Message 1 of 9 (220 Views)

# how to measure the area of a region, defined on a TIN Surface

220 Views, 8 Replies
12-06-2013 03:46 AM

Hello to All,
I’d like to ask how I can measure the area of a region, defined on a TIN surface. ( i.e. the area of the bounded topographic terrain )

Regards

Silvi

*Expert Elite*
Posts: 3,417
Registered: ‎08-01-2008
Message 2 of 9 (208 Views)

# Re: how to measure the area of a region, defined on a TIN Surface

12-06-2013 04:53 AM in reply to: Chiby
Either look at the Surface statistics (for the whole surface) or make a copy of the TIN surface and draw a polyline around the area of interest and add to the surface copy as Non destructive boundary then look at the Surface statistics.

In both cases you can view the 2D and 3D areas
neilyj
(No connection with Autodesk other than using the products in the real world)

IDSP Premium 2014 (mainly Civil 3D 2014 UKIE SP1 & Infraworks with some limited 3ds Max Design)
Win 7 Pro x64, 256Gb SSD, 300Gb 15,000 rpm HDD
16Gb Ram Intel Xeon CPU E5-1607 0 @ 3.00GHz (4 CPUs), ~3.0GHz
NVIDIA Quadro 4000, Dual 27" Monitor, Dell T3600
*Expert Elite*
Posts: 5,442
Registered: ‎05-21-2003
Message 3 of 9 (207 Views)

# Re: how to measure the area of a region, defined on a TIN Surface

12-06-2013 04:58 AM in reply to: Chiby

Select the Surface, right click, select Surface Properties. On the Statistics tab expand Extended. You get 2D & 3D surface area.

Allen Jessup

Member
Posts: 3
Registered: ‎12-06-2013
Message 4 of 9 (193 Views)

# Re: how to measure the area of a region, defined on a TIN Surface

12-06-2013 06:58 AM in reply to: AllenJessup

but I would like to know whether the measured area is the area of the terrain, not the plane one bounded from the boundary in horizontal direction...

Thank you

*Expert Elite*
Posts: 5,442
Registered: ‎05-21-2003
Message 5 of 9 (190 Views)

# Re: how to measure the area of a region, defined on a TIN Surface

12-06-2013 07:02 AM in reply to: Chiby

Chiby wrote:

measured area is the area of the terrain, not the plane one bounded from the boundary in horizontal direction...

How are you seeing that as being different from the 3D area?

Allen

*Expert Elite*
Posts: 3,417
Registered: ‎08-01-2008
Message 6 of 9 (187 Views)

# Re: how to measure the area of a region, defined on a TIN Surface

12-06-2013 07:03 AM in reply to: AllenJessup
The OP might have been confused by your screenshot as the 2D and 3D areas are identical...
neilyj
(No connection with Autodesk other than using the products in the real world)

IDSP Premium 2014 (mainly Civil 3D 2014 UKIE SP1 & Infraworks with some limited 3ds Max Design)
Win 7 Pro x64, 256Gb SSD, 300Gb 15,000 rpm HDD
16Gb Ram Intel Xeon CPU E5-1607 0 @ 3.00GHz (4 CPUs), ~3.0GHz
NVIDIA Quadro 4000, Dual 27" Monitor, Dell T3600
*Expert Elite*
Posts: 5,442
Registered: ‎05-21-2003
Message 7 of 9 (185 Views)

# Re: how to measure the area of a region, defined on a TIN Surface

12-06-2013 07:07 AM in reply to: neilyj

Not quite identical. But very close.

I didn't have a surface in the drawing I had open. So I just drew 2 3D polylines and created a surface using them as breaklines. There wasn't much of an elevation difference.

Allen

*Expert Elite*
Posts: 3,417
Registered: ‎08-01-2008
Message 8 of 9 (178 Views)

# Re: how to measure the area of a region, defined on a TIN Surface

12-06-2013 07:12 AM in reply to: AllenJessup

Thought that's what you did.....here's one I'm working on...

neilyj
(No connection with Autodesk other than using the products in the real world)

IDSP Premium 2014 (mainly Civil 3D 2014 UKIE SP1 & Infraworks with some limited 3ds Max Design)
Win 7 Pro x64, 256Gb SSD, 300Gb 15,000 rpm HDD
16Gb Ram Intel Xeon CPU E5-1607 0 @ 3.00GHz (4 CPUs), ~3.0GHz
NVIDIA Quadro 4000, Dual 27" Monitor, Dell T3600
Member
Posts: 3
Registered: ‎12-06-2013
Message 9 of 9 (177 Views)

# Re: how to measure the area of a region, defined on a TIN Surface

12-06-2013 07:14 AM in reply to: Chiby

Thank you again,

I just have done some examples and found out that this is exactly what I need...

Regards

Recently Solved