Could some one please help me with this:
I have an existing survey surface, and I want to know how much cubic yard of materials to fill up from the bottom to elevation 876. See attached image for detail. Here is what i am going to do and please correct me if my way is right way to do or not:
- i will create a surface of the fill area (from bottom cotours up to el 876) then do a volume surface bwt existing ground surface and the new fill area surface to get the volume of it? Is this a right way to do?
Thanks and Regards.
If the finished surface is all at 876 then extract the 876 contour and use that as a breakline/boundary in a new surface then volume surface with EG as base and 876 surface as comparison.
draw a rectangle at 876, create a surface from it and use this as the comparison surface (possible easier as no triangles to trim out on concave areas)
You could also draw a rough pline around the 876 contour and run reportsurfboundedvolume with the pline as the boundary and specify a datum of 876.
Incidentally at the top left of the screendump the contours appear to drop down to around 873.5 in which case this will be calculated with a vertical "cookie cut edge" which may or may not affect the volume greatly
Please patience with me as i am a new in C3D.
"draw a rectangle at 876, create a surface from it and use this as the comparison surface (possible easier as no triangles to trim out on concave areas)"
You meant: draw a rough pline around 876, create a surface from this contour line and do a volume surface with EG as base and surface 876 as comparation? i am not understanding? Keep in mind that i want to know the volume of fill material FROM THE BOTTOM OF THE EG surface (el 873) UP TO EL 876?
Yup - I would do the second option.
Draw a feature line, elevation = 876 around your area of interest but slightly larger.
Create a surface
Select the featureline, right click and add to surface as breakline.
Analyze/Volumes, selecting your EG as the base and your 876 elevation surface as the compare. Ignore any cut values.