How can I trim a cut surface against an OG surface?

[Lieblaw]

I'm trying to trim my cut surface to my OG surface and I am wondering how to create this boundary where the cut surface daylights to the OG.  Is there a faster way than to just create 3D Poly lines and try to use the apparent intersection command when free drawing in the 3D polyline?  I essentially want to create a boundary where the two surfaces intersect...what's the best/fastest method to do so?

[doni49]

Welcome to the forum!

Can you post a screenshot?  But I'll offer a few thoughts in the meantime.

I *think* you're saying that the "cut surface" is your PROPOSED surface. 

How was the surface created?  Corridor?  Grading objects/featurelines?  If the latter, you should have a daylight featureline that you can use as your boundary.  If the former, you can set your corridor to use the daylight feature line as the surface boundary.

[Joe-Bouza]

method 1 make a new surface:= FinalGrade >> paste OG into >> paste the cut surface in that order

method 2 (if cut surface include the fill area - presumably) make a volume surface of OG vs cut surface. generate user contour at 0 elevation>> use this as a clip boundary for the cut surface

[Lieblaw]

Thank you for the welcome.

The "cut" surface is my proposed surface.  It was created using contour lines with a stepped offset into several benches on a rock blasting proposal.  I didn't use a corridor but I know it "can" be possible but for time's sake, the contour lines were used.  We're essentially blasting a road with terraced benches through a large rock formation.  As I'm typing this, it seems a corridor will be the most useful in creating the benches and daylight areas as desired....but if I continue to use my contours for my proposed surface, is there a command or method to create an assumed break in each of the surfaces where the proposed surface daylights the OG?  Perhaps I'm dreaming...

[doni49]

How do you define WHERE the daylight is?  If there's a feature line there, then that's (part of) your boundary line.

[Lieblaw · Accepted solution]

It has been figured out...we used MINIMUMDISTBETWEENSURFACES and it gave us the "line" (boundary) we were after.  Thank you for your quick replys and it helped me fidn the answer.  Cheers to you all!